-2p^2+600p=0

Solution for -2p^2+600p=0 equation:

-2p^2+600p=0

a = -2; b = 600; c = 0;
Δ = b2-4ac
Δ = 6002-4·(-2)·0
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{360000}=600$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-600}{2*-2}=\frac{-1200}{-4}
=+300
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+600}{2*-2}=\frac{0}{-4}
=0
$